Reversing a single linked list

#include<iostream>

using namespace std;

class Node {

    public:
    int data;
    Node * next;
    Node(int arg_data) : data(arg_data), next(NULL)
    {}
};

class SingleLinkedList {

    public:

    SingleLinkedList()
    {}

    void Display(Node * head) {

        Node * current = head;
        while (current != NULL) {
            cout << current->data << " ";
            current = current->next;
        }
    }

    Node * Reverse(Node * head) {

        // If head is null or only head (i.e single node), return head.
        if (head == NULL or head->next == NULL)
            return head;

        Node * current = head;
        Node * next_to_current = head->next;
        head->next = NULL;

        while(next_to_current != NULL) {

            Node * temp = next_to_current->next;
            next_to_current->next = current;

            current = next_to_current;
            next_to_current = temp;
        }
        return current;
    }
};

int main() {

   Node * head = new Node(2);
   head->next = new Node(3);
   head->next->next = new Node(5);
   head->next->next->next = new Node(7);
   head->next->next->next->next = new Node(11);
   head->next->next->next->next->next = new Node(13);

   SingleLinkedList s;

   cout <<"\nSingle linked list : " << endl;
   s.Display(head);
   cout <<"\nReversing the single linked list : " << endl;
   head = s.Reverse(head);
   s.Display(head);

   delete head->next->next->next->next->next;
   delete head->next->next->next->next;
   delete head->next->next->next;
   delete head->next->next;
   delete head->next;
   delete head;

   return 0;
}

Single linked list : 
2 3 5 7 11 13 
Reversing the single linked list : 
13 11 7 5 3 2